Enum CustomerInformationInterpretingType
Enum CustomerInformationInterpretingType
Именује се: Aspose.BarCode Асамблеја: Aspose.BarCode.dll (25.4.0)
Дефинише врсту интерпретације (ЦТабел, НТабел или Други) информација о клијентима за АустралијанПост БарЦоде.
public enum CustomerInformationInterpretingType
Fields
CTable = 0
Користите ЦТабел да бисте интерпретирали информације о клијентима. омогућава А..З, а..З, 1..9, простор и # знак.
NTable = 1
Користите NTable да бисте интерпретирали информације о клијентима. омогућава цифре.
Other = 2
Немојте интерпретирати информације купаца. дозвољава само 0, 1, 2 или 3 симбола.
Examples
Ови узорци показују како генерисати и препознати аустралијски поштански бар код
//This sample shows how to generate and recognize Australia Post barcode with CTable Interpreting Type.
using (BarcodeGenerator generator = new BarcodeGenerator(EncodeTypes.AustraliaPost, "5912345678ABCde"))
{
generator.Parameters.Barcode.AustralianPost.AustralianPostEncodingTable = CustomerInformationInterpretingType.CTable;
using (Bitmap image = generator.GenerateBarCodeImage())
using (BarCodeReader reader = new BarCodeReader(image, DecodeType.AustraliaPost))
{
reader.BarcodeSettings.AustraliaPost.CustomerInformationInterpretingType = CustomerInformationInterpretingType.CTable;
foreach (BarCodeResult result in reader.ReadBarCodes())
{
Console.WriteLine("BarCode Type: " + result.CodeType);
Console.WriteLine("BarCode CodeText: " + result.CodeText);
}
}
}
Using generator As New BarcodeGenerator(EncodeTypes.AustraliaPost, "5912345678ABCde")
generator.Parameters.Barcode.AustralianPost.AustralianPostEncodingTable = CustomerInformationInterpretingType.CTable
Using image As Bitmap = generator.GenerateBarCodeImage()
Using reader As New BarCodeReader(image, DecodeType.AustraliaPost)
reader.BarcodeSettings.AustraliaPost.CustomerInformationInterpretingType = CustomerInformationInterpretingType.CTable
For Each result As BarCodeResult In reader.ReadBarCodes()
Console.WriteLine("BarCode Type: " + result.CodeTypeName)
Console.WriteLine("BarCode CodeText: " + result.CodeText)
Next
End Using
End Using
End Using
//This sample shows how to generate and recognize Australia Post barcode without Customer Interpreting Type.
[C#]
using (BarcodeGenerator generator = new BarcodeGenerator(EncodeTypes.AustraliaPost, "59123456780123012301230123"))
{
generator.Parameters.Barcode.AustralianPost.AustralianPostEncodingTable = CustomerInformationInterpretingType.Other;
using (Bitmap image = generator.GenerateBarCodeImage())
using (BarCodeReader reader = new BarCodeReader(image, DecodeType.AustraliaPost))
{
reader.BarcodeSettings.AustraliaPost.CustomerInformationInterpretingType = CustomerInformationInterpretingType.Other;
foreach (BarCodeResult result in reader.ReadBarCodes())
{
Console.WriteLine("BarCode Type: " + result.CodeType);
Console.WriteLine("BarCode CodeText: " + result.CodeText);
}
}
}
Using generator As New BarcodeGenerator(EncodeTypes.AustraliaPost, "59123456780123012301230123")
generator.Parameters.Barcode.AustralianPost.AustralianPostEncodingTable = CustomerInformationInterpretingType.Other
Using image As Bitmap = generator.GenerateBarCodeImage()
Using reader As New BarCodeReader(image, DecodeType.AustraliaPost)
reader.BarcodeSettings.AustraliaPost.CustomerInformationInterpretingType = CustomerInformationInterpretingType.Other
For Each result As BarCodeResult In reader.ReadBarCodes()
Console.WriteLine("BarCode Type: " + result.CodeTypeName)
Console.WriteLine("BarCode CodeText: " + result.CodeText)
Next
End Using
End Using
End Using